Find The Sum Of Exterior Angles Of A Polygon
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Thus 70 60 65 40 x 360 235 x 360 X 360 235 125 Example 2.
Find the sum of exterior angles of a polygon. The sides of the polygon meet at the vertices forming angles. Also the measure of each exterior angle of an equiangular polygon 360n. Therefore all its exterior angles measure the same as well that is 120.
One important property about a regular polygons exterior angles is that the sum of the measures of the exterior angles of a. The sum of the exterior angles of a regular polygon will always equal 360 degrees. 1Find the exterior angle of a regular octagon.
They are Supplementary Angles. Extend each side of the polygon forming an exterior angle at each vertex. A Polygon is any flat shape with straight sides.
In geometry an icosidigon or icosikaidigon or 22-gon is a twenty-two-sided polygon. To find the value of a given exterior angle of a regular polygon simply divide 360 by the number of sides or angles that the polygon has. Thus the sum of exterior angles can be obtained from the following formula.
7 rows Since the sum of exterior angles of any polygon is always equal to 360 we can divide by. For any closed structure formed by sides and vertex the sum of the exterior angles is always equal to the sum of linear pairs and sum of interior angles. 2What is the polygon whose sum of interior angles is 1800.
The sum of the measures of the interior angle of any polygon is the number of sides minus 2 multiplied by 180. Therefore we can calculate the measure of one of the exterior angles of a regular polygon by dividing 360 by the number of sides of the regular polygon. Find the sum of exterior angles obtained on producing in order the sides of a polygon with.
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